(1/9)-(5/3x)+25x^2

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Solution for (1/9)-(5/3x)+25x^2 equation:


x in (-oo:+oo)

25*x^2-((5/3)*x)+1/9 = 0

25*x^2+(-5/3)*x+1/9 = 0

25*x^2-5/3*x+1/9 = 0

DELTA = (-5/3)^2-(1/9*4*25)

DELTA = -25/3

DELTA < 0

x belongs to the empty set

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